8d^2+5d-7=0

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Solution for 8d^2+5d-7=0 equation: 



8d^2+5d-7=0

a = 8; b = 5; c = -7;
Δ = b2-4ac
Δ = 52-4·8·(-7)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{249}}{2*8}=\frac{-5-\sqrt{249}}{16}
$


$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{249}}{2*8}=\frac{-5+\sqrt{249}}{16}
$

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